2.6 Equipotential Surfaces - Electrostatic Potential and Capacitance - Class 12 Physics

2.6 Equipotential Surfaces

An equipotential surface is a surface with a constant value of potential at all points on the surface. For a single point charge q, the potential is given by Equation (2.8):

V = (1/4πε0) (q/r)

This shows that V is a constant if r is constant. Thus, equipotential surfaces of a single point charge are concentric spherical surfaces centred at the charge.

FIGURE 2.9: For a single point charge q (a) equipotential surfaces are spherical surfaces centred at the charge, and (b) electric field lines are radial, starting from the charge if q > 0.


is in 2 parts: for a single point charge +q, (a) equipotential surfaces are spherical in nature, centred at the charge, and (b) electric field lines due to the charge are radially outwards, starting from the charge. By Dr TKBansal, & ArunS.

Now the electric field lines for a single charge q are radial lines starting from or ending at the charge, depending on whether q is positive or negative. Clearly, the electric field at every point is normal to the equipotential surface passing through that point. This is true in general: for any charge configuration, equipotential surface through a point is normal to the electric field at that point. The proof of this statement is simple.

If the field were not normal to the equipotential surface, it would have non-zero component along the surface. To move a unit test charge against the direction of the component of the field, work would have to be done. But this is in contradiction to the definition of an equipotential surface: there is no potential difference between any two points on the surface and no work is required to move a test charge on the surface. The electric field must, therefore, be normal to the equipotential surface at every point. Equipotential surfaces offer an alternative visual picture in addition to the picture of electric field lines around a charge configuration.

For a uniform electric field E vector, say, along the x -axis, the equipotential surfaces are planes normal to the x -axis, i.e., planes parallel to the y-z plane (Fig.2.10).

FIGURE 2.10 Equipotential surfaces for a uniform electric field.


shows a horizontal uniform electric field represented by equispaced field lines parallel to the x-axis, & the equipotential surfaces due to this field are shown by vertical planes parallel to the y-z plane.By Dr TKBansal & ArunS.

Equipotential surfaces for (a) a dipole and (b) two identical positive charges are shown in Fig.2.11.

FIGURE 2.11 (a): Some equipotential surfaces for a dipole


shows 2 charges, −q and + q seperated by some distance on a horizontal line. Equipotential surfaces due to these charges are shown to be oval shaped circles surrounding each charge independently. By Dr TKBansal & ArunS.

FIGURE 2.11 (b): Some equipotential surfaces for two identical positive charges.


shows 2 charges +q each separated by some distance. Here again, equipotential surfaces are ovel shaped circles enclosing each charge individually. As we move farther the surfaces merge & form elliptical surfaces enclosing the 2 charges together.

2.6.1 Relation between field and potential

Consider two closely spaced equipotential surfaces A and B (Fig.2.12) with potential values V and


V + δV, where δV is the change in V in the direction of the electric field E vector.

FIGURE 2.12 From the potential to the field.


shows an electric field E vector directed vertically upwards. A & B are 2 equipotential surfaces at potentials of V & V+δV, & separated by a small distance of δl. A & B are points on surfaces A & B respectively. By DrTKBansal

Let P be a point on the surface B. δl is the perpendicular distance of the surface A from P. Imagine that a unit positive charge is moved along this perpendicular from the surface B to surface A against the electric field. The work done in this process is |E vector | δl.

This work equals the potential difference V A − VB.

Thus,


|E vector |δl = V − (V + δV) = − δV


i.e., |E vector| = − δV/δl .. .. (2.20)

or more accurately, |E vector| = − dV/dl

Since δV is negative, δV = − |δV|.


we can rewrite Equation (2.20) as

|E vector| = − δV/δl = + |δV|/δl .. .. (2.21)

We thus arrive at two important conclusions concerning the relation between electric field and potential:

(i) Electric field is in the direction in which the potential decreases steepest.

(ii) Its magnitude is given by the change in the magnitude of potential per unit displacement normal to the equipotential surface at the point.